From table for 12-ineh wall, 3 sq. ft.= OS bricks.
Adding together the various totals for the piers, we have: Total number of bricks in piers = 570 ± 330 + 338 + 165 + 6S = 1,471 bricks.
For total number of bricks in footings, basement walls, area-way walls, and piers, we have: 3,038 + 18.539 + 3,105+1,471 = 26,153 bricks.
This is wall measure, and not actual number of bricks.
If the actual number of bricks is desired, we should proceed as follows: Find the actual cubic contents of all brickwork, and multiply the result by 17—that is, by the number of bricks contained in a cubic foot of wall with ordinary mortar joints.
The cubic contents will be figured as follows: Footings121' x 2/3' X 1 2/3' = 133 cubic feet.
Walls121' x x = DOS cubic feet.
&distracting (63 ± 21) X 1 = 81 cubic feet for door and windows, we have: 908 —84 = 824 cubic feet.
Area-Way11%' X 6' X X 2 = 136 cubic feet.
Front Piers7' X 155' X 11/2' X 2 = 25 cubic feet. 4' X 1)4' X X 2 = 14 cubic feet.
Basement Piers7%,' X 1' X l' X 2 =15 cubic feet.
16-Inch Pier at Rear 4' X 1%' =7 cubic feet.
8x12-Inch Pier at Rear 4' x x 2/3' = 2 2/3, or 3 cubic feet.
Total cubic contents.
133 + 824 + 134 + 25 + 14 + 15 + 7 + 3 = 1,153 cubic feet.
Allowing 17 bricks to the cubic foot., we have: 1,159 X 17= 19.703 bricks as the actual number of bricks needed below the first flour.
If we wish to cheek up the wall measure, which was 26,153, by applying the rule of 221/2 bricks per cubic foot of wall, we find: 1,159 X 22% =26,078 brick; which is very close to the figure found by the use of Table XI.
Walls from Top of First-Floor Joists to Roof. Since the method of procedure has now been outlined, we shall go directly to the house plans for our dimensions in each case, and proceed with less detail.
Side Walls— :37 ft. X 13% ft.= 509 sq. ft. From table for Sinch wall, 500 sq. ft. = 7,50o bricks 9 sq. ft.= 135 bricks Total, 7,635 bricks Multiplying this by 2 for 2 walls, we have: 2 X 7.635 = 15,270 brief:.
Add for gables on sides 22' X 11' X V. = 121 sq. ft.
(Area of a triangle ik equal to one•half the product obtained by multiplying the length of the base by the height.) From table for 8.inch wall, 100 sq. ft.= 1,500 bricks 20 sq. ft.= 300 brie'.
1 sq. ft.= 15 bricks Then, 13,270+ 3,630 = 19,900 bricks.
Deducting opening in walls, making same allowance as before, 1 spare 36" X 58" =2.088 sq. in.
2 spaces 38" x 58" = 3,248 sq. is 1 space 66' X 76" —3,016 eq. in. 1 space 44" X Mt" = 2.728 eq. in.
Total, 13,090 sq. in.
13,080 = 91 sq. ft. of wall surface. 144 From table for 6.inrh wall, 90 sq. ft.= 1,350 bricks 1 sq. ft. -= 15 bricksTotal. 1,365 bricks Deducting 1,365 from 10,900, we have: 19,900.— 1,365 = 17,535 bricks This is wall measure for side 'walls of building.
For front and rear end walls, the figuring will be done as follows: End Walla—ErentDeduct thickness of side walls, which has already been figured in in getting number of bricks in side walls.
201/2' X 13%' =282 sq. ft.
with gable, Ys X 22' X 11' =121 sq. ft.
403 sq. ft.
Deducting front bay windon• opening in wall, 12' X 10' =- 12U sis. ft.
383 sq. ft.
Deducting a leo front door opening.
X 7%' = 25 sq. ft.
258 sq. ft.
and deducting windows, 1 space. X 40" = 960 sq. in 1 space, 66" x 03" = 4.093 sq. in.
5,052 rel. in.
5,052 144 258-35=223 sq. ft.
Add for bricks in front bay window: Length around front bay =141/4 ft.
Height = 10 ft.
x 10' = 145 sq. ft.
Deduct window openings, 1 space 54" x 76" = 4,104 sq. in.
2 spaces 33" x 70" = 4,864 sq. in.
0.066 sq. in.
8,960 144 115 —62 =403 sq. ft. of wall surface.
Adding 223 sq. ft. of surface in front wall and 83 sq. ft. in front bay, we have, 223 + 03 300 eq. ft. From table for 8-inch wall, 200 sq. ft.= 3,000 bricks 100 sq. ft.= 1.500 bricks 0 sq. ft.= 90 bricks Total. 4.590 bricks fur front end wall of house.
Rear Wall— x 13%' = 202 sq. ft., with gable, Vs X 22' x 11' =121 eq. ft.
403 eq. ft.
Deducting rear bay window opening in wall, 11' x 10' = 110 sq. ft.
208 eq. it.
Deducting also rear els, X = 22 m. ft.