271 sq. ft.
and deducting window openings.
1 space, 56" X 70" = 2,520 sq. in.
1 space, 38" x 70" = 2,660 sq. is 5,180 sq. in.
5,100 = 36 sq. ft. 144 271 — 36 = 235 sq. ft. of wall surface.
Add for bricks in rear bay window: Length around mar bay= 14 ft.
Height = 9 ft.
14' X 9' = 126 sq. ft.
Deduct window openings, 2 spasms, 28" X 76" = 4.206 sq. in 1 spare, 44" x 70" = 3,344 sq. in.
7.600 sq. in.
7.600 =53 sq. ft. 144 126-53 = 73 sq. ft.
Adding 235 sq. ft. of surface in rear wall. and 73 sq. ft.
of surface in rear bay, gives: 235 + 73 = 308 sq. ft.
From table for 8-inch wall.
200 sq. ft. = 3,000 bricks 100 sq. ft.= 1,500 bricks 8 eq. ft. = 120 bricks Total, 4.620 bricks for rear end wall of house.
Total Wall Measure above First Floor Sides . 17,535 Front 4,500Rear 4,620 26,745 bricks To determine kiln count, or actual munber of bricks, we may, as before, find the actual cubic contents of the walls above the top of the first floor joists, and then multiply by 17. Or, we may multiply the above "wall measure" number, 26,745, by 17, and divide by 26,745 X 17 =20,207 bricks, "kiln count." As a matter of interest and as a check on the work, we shall go back and add up the cubic contents of the walls above the top of the first-floor joists.
From the previous work, Side walls, sq. ft.= (509 4- 121) X 2 = 1,260 Deducting openings. sq. ft., 91 Total, 1,783 sq. ft.
Multiplying this wall surface by the thickness, 8 inches, or 2/3 foot, 1,783 X 2/3' = 1,189 cubic feet.
Applying the rule of 17 bricks to the cubic foot, we have: 1,109 X 17 =20,213 bricks, "kiln count," which checks approximately with the previous result.
ChimneysOne chimney feet high, with 8x12-inch flue: From page 55 we have seen that for all 8x12-inch flue 35 bricks are needed for each foot of height: 331/4 X 35=1,173 bricks.
One chimney feet high with 8a8inch flue: It has been demonstrated that for an 8x8-inch flue 30 bricks are needed for each foot of height: 331/2 X 30= 1,005 bricks.
Total for 2 chimneys: 1,173 + 1,005 = 2,178 bricks.
If it is desired, these figures may be checked by the chimney rule given on page 54.
Adding the numbers of bricks determined from the previous calculations, we find that the following bricks are needed: Wall Measure Basement and footings 26,153 Above first Poor 26,745 Chimneys 2,17855,076 Kiln Count Basement and footings 19,701 Above first floor 20,207 Chimneys 2,17842,088 A nearer approimation may be reached by deducting the volume of the cut stone shown in the plans. The walls thus far have been figured as solid brick, with no notice taken of the stone.
Cut Stone-FrontPiers: 14" X 4" X 30 "= 1,680 cubic inches. 9" X 4" X 30" = 1,090 cubic inches. Front Wall: 1 piece, 9" X 4" X 30" = 1,000 cubic inches.
1 piece, 6" X 4" X 30" = 720 cubic inches.
1 piece. 6" x 4" X 30" = 7211 cubic inches.
1 piece, 12" X 4" X 30" = 1,440 cubic inches.
1 piece, 12"X 4" x 30" = 1.440 cubic inches.
I piece, X X 30" = 2,430 cubic inches.
1 piece, 75" x 4" X 12" = 3,600 cubic inches.
1 piece, 57" x x 12" = 2,448 cubic inches.
1 piece, 51" x 4" X 12" = 2.448 cubic inches.
1 sill, 60" X 5" X 5" = 1,500 cubic inches.
2 sills, 39" X 5" X 5" = 1,950 cubic inches.
1 sill, 30" X 5" X 5" = 750 cubic inches.
1 sill, 44" X 5" X 10" = 2.200 cubic inches.
1 sill, 24 story. 72" X 5" X 5" = 1,900 milli, inches. 1 fiat arch, 72" x 4" X 18" (average height) =5,184 ruble inches, (Deduct stone water-table if there is one.) Side Walls: I sill, 32" x 5" x 5" = 800 cubic inches.
1 sill, 42" x 5" X 5" = 1,050 cubic inches.
1 sill, 36"X 5" x 5" = 000 cubic inches.
1 sill, 66" X 5" X 5" = 1,650 cubic inches.
1 sill, X 5" X 5" — 900 cubic inches.
2 sills, 28" X 5" X 5" = 1,400 cubic inches.
1 sill. 44" X 5" x 5" =1,100 cubic inches.
1 fiat arch, 72" X 4" X 18" = 5.184 cubic inches.
1 flat arch, 54"X 4" X 13" = 3,240 cubic inches.
I lintel, 52" X 4" X 12" = 2,496 cubic inches.
1 lintel, 42" X 4" X 12" =- 2.016 cubic inches.
1 lintel, 4S" X 4" x 12" = 2,304 cubic inches.
Rear Wall: 1 sill, 40" x 5" X 10" = 2,000 cubic inehes. 1 sill, 38" x 5" X 5" = 950 cubic inches.
1 sill, 36" X 5" X 5" = 900 cubic inches.
2 sills 28" X 5" X 5" = 1,400 cubic incises. 1 sill, 44" X 5" X 5" = 1.100 cubic inches.
1 sill, 40" X 5" X 5" = 1,000 cubic inches. .
Adding to determine the total volume of stonework, we find the result to be: 62,860 cubic incises.
Dividing this by 1,728, the number of cubic inches in a cubic soot: 62,860 =56 (nearly) cubic feet. 1,728 By the rule of bricks to the cubic foot, we should deduct: 221/2 x 56 = 810 bricks froin the "wall measure" of 55,076 bricks.
Or, by the rule of 17 bricks to the cubic foot, we should deduct: 17 X 36 = 612 bricks from the "kiln count" or actual number used, of 42,088.
This would leave the final result as follows: Wall measure Kiln count Allowing 5 per cent for breakage on each of the above amounts, we have: 5 54,266 + x 54,266 = 56,979 bricks 100 5 41,476 + — X 41,476 = 43,549 bricks 100 These are the approximate numbers needed according to the two meth ods of figuring. In practice these 1111111_ hers would probably be treated as. 57 thousand and 44 thousand.
No attempt has been made here to separate the various kinds of brick, as the intention is to show the method of obtaining the number of standard bricks which are needed. By applying the same methods, the number of each kind of brick in a house where several qualities are used, may be found.
On large jobs of brickwork, it is often usual for the contractor to specify a minimum size for the bricks so as to guard against losses from estimating that a certain number of bricks will build a certain number of cubic feet of wall.
Thickness of mortar joints is also a quantity to be figured on in determining actual number of brick. This point was referred to on page 52.